29 May
2009
29 May
'09
6:58 a.m.
On Thursday 28 May 2009 13:17:04 Kartik Muralidharan wrote:
But how would batman choose the next hop if at every node there are two interfaces available. The ideal ofcourse would be 11a->11b->11a->11b->11a on each hop.
If all nodes have 2 interfaces its hard to predict whether it will be: 11a->11b->11a->11b->11a or 11b->11a->11b->11a->11b
If the link qualities are all equal batman we choose the fastest path (lowest latency).
Regards, Marek