On Thursday 28 May 2009 13:17:04 Kartik Muralidharan wrote:
But how would batman choose the next hop if at every
node there are two
interfaces available. The ideal ofcourse would be
11a->11b->11a->11b->11a on each hop.
If all nodes have 2 interfaces its hard to predict whether it will be:
11a->11b->11a->11b->11a
or
11b->11a->11b->11a->11b
If the link qualities are all equal batman we choose the fastest path (lowest
latency).
Regards,
Marek