9 Mar
2012
9 Mar
'12
2:36 p.m.
On Friday, March 09, 2012 22:07:37 Benjamin Henrion wrote:
C=S will probably have a better TQ if it is not getting as much interference due to collisions. A will get to know about this in the path TQ. Better still, B-C will also probably have a better TQ, since the link C=S is not interfering with it. So the path TQ is even better. A gets all this.
How do you compute the TQ?
I suggest reading chapter 3.1 (specifically 3.1.3) of the excellent network coding paper[1] written by our catwoman specialists. It is very well written and contains the most comprehensive general overview about batman-adv in existence.
Regards, Marek
[1] http://downloads.open-mesh.org/batman/papers/batman-adv_network_coding.pdf